A train travelling at $250 k m / h$ overtakes a cyclist who is moving at $10 k m / h$ in $45 s e c o n d s$ . Find the length of the train in meters?

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Solution

Step 1 : Finding the uniform speed
Speed of the Train $= 250 k m / h$
Speed of the cycle $= 10 k m / h$
The train overtakes the cyclist who travels in $45 s e c o n d s$ with a speed of $10 k m / h$
Now Uniform speed $= (250 - 10) k m / h$
Uniform speed $= 240 k m / h$
Step 2 : Finding the length of the train
Then the uniform speed of the cyclist and the train = $240 x (5 / 18) m / s$
The length of the train = $\frac{240 \times 5 \times 45}{18} = 3000$
Hence, the length of the train $3000 m$

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A train travelling at250km/h overtakes a cyclist who is moving at 10km/h in45seconds. Find the length of the train in meters?

A train travelling at $250 k m / h$ overtakes a cyclist who is moving at $10 k m / h$ in $45 s e c o n d s$ . Find the length of the train in meters?