Then, the length of the second train is (x) metres.2
Relative speed =(48+42)kmph=(90×5)m/sec=25m/sec.18
∴[+(2)]xx=12 or 3
x= 300 or = 200.x
252
Length of first train = 200 m.
∴
Let the length of platform be metres.
y
Speed of the first train =(48×5)
m/sec=403m/sec.
18
(200 + ) x
∴y3
340=45
600 + 3 = 1800
⇒y
=400m.
⇒y