a train travelling at a spedof 90 kmh-1 Brakesare are appliedso as to produce a uniform accleration of 0.5 ms-2 find howfar thetyrain will go before it is bought to rest

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Solution

Here, initial speed, u = 90 kmh-1 = 90 x(5/18) = 25 ms-1
Acceleration, a = – 0.5 ms-2
Train brought to rest, so final speed, v = 0
From third equation of motion, v2 = u2 + 2as
0 = (25)2 + 2 x 0.5 x s
0 = 625 – s
s = 625 m

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a train travelling at a spedof 90 kmh-1 Brakesare are appliedso as to produce a uniform accleration of 0.5 ms-2 find howfar thetyrain will go before it is bought to rest

Here, initial speed, u = 90 kmh-1 = 90 x(5/18) = 25 ms-1 Acceleration, a = – 0.5 ms-2 Train brought to rest, so final speed, v = 0 From third equation of motion, v2 = u2 + 2as 0 = (25)2 + 2 x 0.5 x s 0 = 625 – s s = 625 m

Here, initial speed, u = 90 kmh-1 = 90 x(5/18) = 25 ms-1
Acceleration, a = – 0.5 ms-2
Train brought to rest, so final speed, v = 0
From third equation of motion, v2 = u2 + 2as
0 = (25)2 + 2 x 0.5 x s
0 = 625 – s
s = 625 m