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Question

A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/h more. Find the original speed of the train in km/hr.

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Solution

Let x= Original Speed

we know that distancespeed=time

So as per the question the following equation can be formed
360x360x+5=4860 [1 hour = 60 minutes]

1x1x+5=48601360
5x2+5x=1450
x2+5x2250=0
x245x+50x2250=0
x(x45)+50(x45)=0
(x45)(x+50)=0
x=45,50
As the speed can't be negative so,

x=45

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