A train travels $40$ % faster than a car. Both start from point A at the same time and reach point B, $140 k m$ away at the same time. On the way the train takes $25$ minutes for stopping at the stations. What is the speed (in km/hr) of the train?

67

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134.4

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145.9

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160

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Solution

The correct option is B $134.4$
Let the speed of train and car be $7 x$ and $5 x$ respectively
$\frac{140}{5 x} - \frac{140}{7 x} = \frac{25}{60}$
$x = 19.2$
Hence, speed of train $= 7 \times 19.2 = 134.4 k m / h r$

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A train travels 40% faster than a car. Both start from point A at the same time and reach point B, 140km away at the same time. On the way the train takes 25 minutes for stopping at the stations. What is the speed (in km/hr) of the train?

The correct option is B 134.4Let the speed of train and car be 7x and 5x respectively1405x−1407x=2560x=19.2Hence, speed of train =7×19.2=134.4km/hr

A train travels $40$ % faster than a car. Both start from point A at the same time and reach point B, $140 k m$ away at the same time. On the way the train takes $25$ minutes for stopping at the stations. What is the speed (in km/hr) of the train?

The correct option is B $134.4$
Let the speed of train and car be $7 x$ and $5 x$ respectively
$\frac{140}{5 x} - \frac{140}{7 x} = \frac{25}{60}$
$x = 19.2$
Hence, speed of train $= 7 \times 19.2 = 134.4 k m / h r$