A train travels at a certain average speed for a distance of 54 km and then travels a distance of 63 km at an average speed of 6 km/hr more than the first speed. If it takes 3 hours to complete the total journey, what is its first speed?
Distance = 54 km
Let the average speed be x
Distance= 63km
The average speed to cover this distance = x+6
Total Time Taken= 3 hr.
D/S =t
therefore, 54/x + 63/x+6 = 3
54(x+6) +63x =3x(x+6)
3x2−99x−324=0
x=36, -3
Hence x= 36km/hr