A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than than its original speed. If it takes 3 hours to complete the total journey, what is the original average speed?

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Solution

It is given that a train travels a distance of 63 km with a certain average speed and 72 km with a speed which is 6 km/hr more than the original average speed.

Time taken for the whole journey is 3hr.

We have to find out the original average speed of the train.

Let the original average speed of the train = x km/hr

While covering the distance of 72 km, the speed of train

Total time taken by the train

Therefore

Dividing both sides by3

Speed cannot be negative

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OR
A train travels at a certain average speed for a distance of 63 km and then travels at a distance of 72 km at an average speed of 6 km/ hr more than its original speed. If it takes 3 hours to complete total journey, what is the original average speed ?

A train travels at a certain average speed for a distance of 63 km and then Travels at a distance of 72 km at an average speed of 6 km per hour more than its original speed if it takes 3 hours to complete total journey what is the original speed ?

My solution :

63/x + 72/(x+6) = 3

After solving I got the answer => x=42

I wrote the answer as the train's original average speed is 42km/hr .

Is it correct ??????

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