A train travels between two stations 'P' and 'Q'. It travels with a velocity of $20 k m h$ $^{- 1}$ from P to Q and returns to station P with a velocity of $30 k m h$ $^{- 1}$ . The average speed for the total journey.

25 k m h^{- 1}

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24 k m h^{- 1}

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6.67 m s^{- 1}

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0 m s^{- 1}

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Solution

The correct option is B $24 k m h^{- 1}$
$P \leftrightarrow Q$
Average speed $= \frac{2 d}{\frac{d}{20} + \frac{d}{30}}$
$= \frac{2 \times 600}{50} = 24 k m h^{- 1}$

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A train travels between two stations 'P' and 'Q'. It travels with a velocity of 20kmh−1 from P to Q and returns to station P with a velocity of 30kmh−1. The average speed for the total journey.

The correct option is B 24kmh−1P↔QAverage speed =2dd20+d30=2×60050=24kmh−1

A train travels between two stations 'P' and 'Q'. It travels with a velocity of $20 k m h$ $^{- 1}$ from P to Q and returns to station P with a velocity of $30 k m h$ $^{- 1}$ . The average speed for the total journey.

The correct option is B $24 k m h^{- 1}$
$P \leftrightarrow Q$
Average speed $= \frac{2 d}{\frac{d}{20} + \frac{d}{30}}$
$= \frac{2 \times 600}{50} = 24 k m h^{- 1}$