A train travels between two stations 'P' and 'Q'. It traves with a velocity $20 k m h^{- 1}$ from P to Q and returns to station P with a velocity $30 K m h^{- 1}$ . The average speed for the total journey.

Open in App

Solution

lets the distance between P and Q be $x k m$ ,
case(1): From P to Q
$u = 20 k m / h$
$t_{1} = \frac{x}{20} h$
Case(2): From Q to P
$v = 30 k m / h$
$t_{2} = \frac{x}{30} h$
The total distance traveled by train is $d = 2 x k m$
The total time taken by the train,
$t = t_{1} + t_{2} = \frac{5 x}{60}$
The average speed,
$v_{a v g} = \frac{d}{t} = \frac{2 x}{\frac{5 x}{60}}$
$v_{a v g} = \frac{2 x}{5 x} \times 60$
$v_{a v g} = 24 k m / h$

Suggest Corrections

Similar questions

Q. A train travels between two stations 'P' and 'Q'. It travels with a velocity of

20 k m h

^{- 1}

from P to Q and returns to station P with a velocity of

30 k m h

^{- 1}

. The average speed for the total journey.

Q. The train travels with a speed of

60 k m H^{- 1}

from station A to station B and then come back with a speed

80 k m H^{- 1}

from station B to station A. Find The average velocity of train.

Q. A train travels with a speed of

60 k m h^{- 1}

from station A to station B and then comes back with a speed

80 k m h^{- 1}

from station B to station A. i) The average speed and ii) the average velocity of the train

Q. A car travels from A to B at a, speed of

20 k m h^{- 1}

and returns at a speed of

30 k m h^{- 1}

. The average speed of the car for the whole journey is:

A train takes 2 h to reach station B from station A,and then 3 h to return from station B to station A.The distance between the two stations is 200 km.Find:(i)the average speed,(ii) the average velocity of the train.

Join BYJU'S Learning Program

A train travels between two stations 'P' and 'Q'. It traves with a velocity 20kmh−1 from P to Q and returns to station P with a velocity 30Kmh−1. The average speed for the total journey.

lets the distance between P and Q be xkm,case(1): From P to Qu=20km/ht1=x20hCase(2): From Q to Pv=30km/ht2=x30hThe total distance traveled by train is d=2xkmThe total time taken by the train,t=t1+t2=5x60The average speed,vavg=dt=2x5x60vavg=2x5x×60vavg=24km/h

A train travels between two stations 'P' and 'Q'. It traves with a velocity $20 k m h^{- 1}$ from P to Q and returns to station P with a velocity $30 K m h^{- 1}$ . The average speed for the total journey.