A train travels from one station to another station Y at the rate of $20 k m / h r$ and returns at the rate of $30 k m / h r$ . The average speed of the total journey is

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Solution

Let A be the one station
B be the other station
A to B is 20 km/hr
Let A to B = X = 20 km/hr
B to A = Y = 30 km/hr
$\frac{2 \times Y}{X + Y} = \frac{2 (20) (30)}{20 + 30}$
$= \frac{40 (30)}{50}$
$= \frac{1200}{50}$
$= 24 k m / h r$

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A train travels from one station to another station Y at the rate of 20km/hr and returns at the rate of 30km/hr. The average speed of the total journey is

Let A be the one stationB be the other stationA to B is 20 km/hrLet A to B = X = 20 km/hrB to A = Y = 30 km/hr2×YX+Y=2(20)(30)20+30=40(30)50=120050=24km/hr

A train travels from one station to another station Y at the rate of $20 k m / h r$ and returns at the rate of $30 k m / h r$ . The average speed of the total journey is

Let A be the one station
B be the other station
A to B is 20 km/hr
Let A to B = X = 20 km/hr
B to A = Y = 30 km/hr
$\frac{2 \times Y}{X + Y} = \frac{2 (20) (30)}{20 + 30}$
$= \frac{40 (30)}{50}$
$= \frac{1200}{50}$
$= 24 k m / h r$