A train travels with a speed of $60 k m h^{- 1}$ from station A to station B and then comes back with a speed $80 k m h^{- 1}$ from station B to station A. The distance between station A and station B is 960km. The time of travel of the train is:

28 h r

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14 h r

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35 h r

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42 h r

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Solution

The correct option is A $28 h r$
$⟹ t = \frac{960}{60} + \frac{960}{80}$
$⟹ t = 16 + 12 = 28 h r$

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A train travels with a speed of 60kmh−1 from station A to station B and then comes back with a speed 80kmh−1 from station B to station A. The distance between station A and station B is 960km. The time of travel of the train is:

The correct option is A 28hr⟹t=96060+96080⟹t=16+12=28hr

A train travels with a speed of $60 k m h^{- 1}$ from station A to station B and then comes back with a speed $80 k m h^{- 1}$ from station B to station A. The distance between station A and station B is 960km. The time of travel of the train is:

The correct option is A $28 h r$
$⟹ t = \frac{960}{60} + \frac{960}{80}$
$⟹ t = 16 + 12 = 28 h r$