A train which is moving at an average speed of 40 kmph, reaches its destination on time.When its average speed reduces to 5 kmph, then it reaches its destination 15 minutes late. The distance travelled by the train is

30 km

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40 km

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70 km

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80 km

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Solution

The correct option is B 70 km
Let Distance be D
Time $T_{1}$ , when Speed is 40 km/hr= $\frac{D}{40}$
Time $T_{2}$ , when Speed is 35 km/hr= $\frac{D}{35}$
According to the question,
$\frac{D}{35} - \frac{D}{40} = \frac{15}{60}$
$D = 70$ km

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A train which is moving at an average speed of 40 kmph, reaches its destination on time.When its average speed reduces to 5 kmph, then it reaches its destination 15 minutes late. The distance travelled by the train is

The correct option is B 70 kmLet Distance be DTime T1, when Speed is 40 km/hr=D40Time T2, when Speed is 35 km/hr=D35According to the question,D35−D40=1560D=70 km

The correct option is B 70 km
Let Distance be D
Time $T_{1}$ , when Speed is 40 km/hr= $\frac{D}{40}$
Time $T_{2}$ , when Speed is 35 km/hr= $\frac{D}{35}$
According to the question,
$\frac{D}{35} - \frac{D}{40} = \frac{15}{60}$
$D = 70$ km