A train with a speed of 68 Km/hr has crossed a bike of speed 32 Km/hr in 36 seconds. Then what is the length of the faster train?

360 m

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1296 m

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500 m

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None of these

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Solution

The correct option is A
360 m

For a train to cross a bike, it has to cover a distance equal to its length.

Here, the time for crossing is given as 36 sec and their relative speed (in same direction) = 68 Km/hr - 32 Km/hr = 36 Km/hr or

$36 \times \frac{5}{18} = 10 m / s$

So, $D i s t a n c e = S p e e d \times T i m e$

i.e., $L e n g t h o f t h e f a s t e r t r a i n = 36 s e c \times 10 m / s = 360 m$

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