A transformer has 800 loops in its primary coil and 8,000 loops in its secondary coil. What would be the voltage in the primary coil if the voltage in it secondary coil is 20,000 V.

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Solution

Number of loops in primary coil $N_{p} = 800$
Number of loops in secondary coil $N_{s} = 8000$
Voltage in secondary coil $V_{p} = 20000 V$
Voltage in primary coil $V_{p} = \frac{N_{p}}{N_{s}} V_{s}$
$⟹ V_{p} = \frac{800}{8000} \times 20000 = 2000 V$

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A transformer has 800 loops in its primary coil and 8,000 loops in its secondary coil. What would be the voltage in the primary coil if the voltage in it secondary coil is 20,000 V.

Number of loops in primary coil Np=800Number of loops in secondary coil Ns=8000Voltage in secondary coil Vp=20000 VVoltage in primary coil Vp=NpNsVs⟹ Vp=8008000×20000=2000 V

Number of loops in primary coil $N_{p} = 800$
Number of loops in secondary coil $N_{s} = 8000$
Voltage in secondary coil $V_{p} = 20000 V$
Voltage in primary coil $V_{p} = \frac{N_{p}}{N_{s}} V_{s}$
$⟹ V_{p} = \frac{800}{8000} \times 20000 = 2000 V$