In a transformer, the number of turns in the primary coil are 140 and that in the secondary coil are 280. If the current in primary coil is 4 A, then the current in the secondary coil is:

Q. An ideal transformer has

500

primary turns and

10

secondary turns. The primary coil carries current

2 A

and its voltage is

11, 000 V

. Current and voltage in the secondary coil will be

Q. The primary coil of a transformer has

1, 32, 000

turns and is connected to A.C. input source of

220 V

. The secondary coil has

2, 400

turns. Find the output voltage.

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A transformer having 2100 turns in the primary and 4200 turns in the secondary has an A.C. source of 120V and 10A connected to its primary coil, then the voltage and current in secondary coil are

The correct option is D 240 V and 5 AIn transformerVsVp=NsNp=IpIsThe voltage in secondary coil isVs=42002100×120=240 VThe current in secondary coil isIs=21004200×10=5 A.

A transformer having $2100$ turns in the primary and $4200$ turns in the secondary has an A.C. source of $120 V$ and $10 A$ connected to its primary coil, then the voltage and current in secondary coil are

The correct option is D $240 V$ and $5 A$
In transformer
$\frac{V_{s}}{V_{p}} = \frac{N_{s}}{N_{p}} = \frac{I_{p}}{I_{s}}$
The voltage in secondary coil is
$V_{s} = \frac{4200}{2100} \times 120 = 240 V$
The current in secondary coil is
$I_{s} = \frac{2100}{4200} \times 10 = 5 A$ .