A transformer is used to convert $200 V A C t o 11 V A C$ .Number of turns in the primary of transformer is $2000 .$ How many turns are there in its secondary? if the efficiency of the transformer is $90 %$ and it can work at maximum load of $10 W .$ Calculate output power and output current.

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Solution

Step1: Given data and assumptions:
Input voltage $E_{p} = 200 V o l t s$
Output Voltage $E_{s} = 11 V o l t s$
Number of turns in primary of transformer $N_{p} = 2000$
Efficiency of the transformer $η = 90 %$
Input power $P_{i n p u t} = 10 W$
Step2: Finding the number of turn in the secondary coil
$B y u \sin g t h e r e l a t i o n : \frac{E_{s}}{E_{p}} = \frac{N_{s}}{N_{p}} \frac{11}{200} = \frac{N_{s}}{2000} N_{s} = \frac{11 \times 2000}{200} N_{s} = 110$
Hence, number of turns in secondary coil is $110 .$
Step3: Finding the output power
Efficiency
$η = \frac{O u t p u t p o w e r (P_{o u t p u t})}{I n p u t P o w e r (P_{i n p u t})} \times 100 90 = \frac{P_{o u t p u t}}{10} \times 100 P_{o u t p u t} = \frac{90 \times 10}{100} P_{o u t p u t} = 9 W$
Hence, the output power is $9 W .$
Step 4: Finding output current
$O u t p u t p o w e r P_{o u t p u t} = E_{s} \times I_{o u t p u t} 9 = 11 \times I_{o u t p u t} I_{o u t p u t} = \frac{9}{11} I_{o u t p u t} = 0.82 A$
Hence, output current is $0.82 A .$

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A transformer is used to convert 200VACto11VAC .Number of turns in the primary of transformer is 2000.How many turns are there in its secondary? if the efficiency of the transformer is 90%and it can work at maximum load of 10W. Calculate output power and output current.

A transformer is used to convert $200 V A C t o 11 V A C$ .Number of turns in the primary of transformer is $2000 .$ How many turns are there in its secondary? if the efficiency of the transformer is $90 %$ and it can work at maximum load of $10 W .$ Calculate output power and output current.