A transformer is used to light 100 W – 110 V lamp from 220 V mains. If the main current is 0.5 A, the efficiency of the transformer is

96 $%$

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90 $%$

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Solution

The correct option is B
90 $%$

$η = \frac{P_{o u t p u t}}{P_{i n p u t}} = \frac{100}{220 \times \frac{1}{2}} = \frac{100}{110} = \frac{10}{11} \approx 90 %$

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