Question

A transformer lowers emf from $220V$ to $12V$ If the number of turns in primary coil is $8800$, how many turns are there in the secondary coil?

• A. 200
• B. 300
• C. 480
• D. 500

Answer 1

The correct option is C 480

$E_p=220V;E_s=12V;N_p=8800;N_s=?$
$\frac{E_p}{E_s}=\frac{N_p}{N_s}$
$\therefore \frac{220}{12}=\frac{8800}{N_s}$
$\therefore N_s=\frac{8800\times 12}{220}=480$
Hence, the number of turns in secondary coil is $480$.