A transformer rated at $10 k W$ is used to connect a $5 k V$ transmission line to a $240 V$ circuit. The ratio of turns in the windings of the transformer is

$5$

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$20.8$

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$104$

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$40$

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Solution

The correct option is B
$20.8$

Step1: Given data and assumptions.
Input power, $P_{i n} = 10 k W = 10000 W$
Secondary voltage, $V_{s} = 240 V$
Primary voltage, $V_{p} = 5 k V = 5000 V$
Step1: Find the ratio of turns in the windings of the transformer.
We know that,
The ratio of turns in the windings of the transformer is equal to the ratio of the primary and secondary voltage.
$\frac{N_{p}}{N_{s}} = \frac{V_{p}}{V_{s}}$
Where,
$N_{p} =$ The number of turns in the primary side.
$N_{s} =$ The number of turns in the secondary side.
Now,
$\frac{N_{p}}{N_{s}} = \frac{5000}{240}$
$\frac{N_{p}}{N_{s}} = 20.8$
Hence, option B is correct.

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A transformer rated at 10kW is used to connect a 5kV transmission line to a 240V circuit. The ratio of turns in the windings of the transformer is

A transformer rated at $10 k W$ is used to connect a $5 k V$ transmission line to a $240 V$ circuit. The ratio of turns in the windings of the transformer is