A transformer steps up an ac supply from 220 to 2200 V. If the secondary coil of the transformer has 2000 turns, Then find the number of turns in its primary coil :

N_{p} = 250 t u r n s

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N_{p} = 300 t u r n s

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N_{p} = 100 t u r n s

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N_{p} = 200 t u r n s

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Solution

The correct option is D $N_{p} = 200 t u r n s$
$V_{p} = 220 V, V_{s} = 2200 V$
$N_{s} = 2000 t u r n s$

$\frac{N_{p}}{N_{s}} = \frac{V_{p}}{V_{s}}$
$\frac{N_{p}}{2000} = \frac{220}{2200}$

$N_{p} = 2000 \times \frac{1}{10}$

$N_{p} = 200 t u r n s$

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