A transistor has a base current of $1 m A$ and emitter current $100 m A$ . The current transfer ratio will be

0.9

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0.99

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1.1

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10.1

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Solution

The correct option is B $0.99$
Given that:
$I_{b} = 1 m A,$
$I_{e} = 100 m A$

Hence, $I_{c} = I_{e} - I_{b} = 100 - 1 = 99 m A$
Current transfer ratio is $\frac{I_{c}}{I_{e}} = \frac{99}{100} = 0.99$

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