Question

A transistor has $\beta$ = 40. A change in base current of 100 $\mu$ A, produces change in collector current

• A. $40\times 100mA$
• B. $(100-40)mA$
• C. $(100+40)mA$
• D. $100/40mA$

Answer 1

Answer: (A)

$40\times 100mA$

$beta=\frac{\Delta I_C}{\Delta I_B}or\Delta I_C=\beta \Delta I_B=40\times 100\mu A$