A transistor is connected in common-emitter C-E configuration- The collector supply is 8 V and the voltage drop across a resistor of 800 - in the collector circuit is 0-5 V- If the current gain factor - is 0-96- find the base current-A- 28 - AB- 24 - AC- 25 - AD- 26 - A

The correct option is D 26 μ Aβ = α/1 α = 24 i_c = 0.5 V/800 Ω = 0.625 × 10^ 3 A i_B = i_c/β = 0.625 × 10^ 3/24 = 26 μ A ...

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Byju's Answer

Standard XII

Physics

Reverse Bias

A transistor ...

Question

A transistor is connected in common-emitter (C-E) configuration. The collector supply is 8V and the voltage drop across a resistor of 800 $Ω$ in the collector circuit is 0.5V. If the current gain factor $(α)$ is 0.96, find the base current.

24 μ A

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25 μ A

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26 μ A

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28 μ A

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Solution

The correct option is C $26 μ A$
$β = \frac{α}{1 - α} = 24 i_{c} = \frac{0.5 V}{800 Ω} = 0.625 \times 10^{- 3} A i_{B} = \frac{i_{c}}{β} = \frac{0.625 \times 10^{- 3}}{24} = 26 μ A$

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A transistor is connected in common-emitter (C-E) configuration. The collector supply is 8V and the voltage drop across a resistor of 800 Ω in the collector circuit is 0.5V. If the current gain factor (α) is 0.96, find the base current.

The correct option is C 26μAβ=α1−α=24ic=0.5V800Ω=0.625×10−3AiB=icβ=0.625×10−324=26μA

A transistor is connected in common-emitter (C-E) configuration. The collector supply is 8V and the voltage drop across a resistor of 800 $Ω$ in the collector circuit is 0.5V. If the current gain factor $(α)$ is 0.96, find the base current.

The correct option is C $26 μ A$
$β = \frac{α}{1 - α} = 24 i_{c} = \frac{0.5 V}{800 Ω} = 0.625 \times 10^{- 3} A i_{B} = \frac{i_{c}}{β} = \frac{0.625 \times 10^{- 3}}{24} = 26 μ A$