A transistor is operated in common-emitter configuration at VC - 2V such that a change in the base current from 100 - A to 200 - A produces a change in the collector current from 5 mA to 10 mA- The current gain is -

The correct option is A 50 Δ I_B=100 μ A Δ I_C=5 mA β= Δ I_CΔ I_B=5×10^ 3100× 10^ 6=50 ...

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Byju's Answer

Standard XII

Physics

Mechanism of Formation of P-N Junction

A transistor ...

Question

A transistor is operated in common-emitter configuration at $V_{C} = 2 V$ such that a change in the base current from $100 μ A$ to $200 μ A$ produces a change in the collector current from 5 mA to 10 mA. The current gain is :

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100

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150

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Solution

The correct option is A 50
$Δ I_{B} = 100 μ A$
$Δ I_{C} = 5 m A$
$β = \frac{Δ I_{C}}{Δ I_{B}} = \frac{5 \times 10^{- 3}}{100 \times 10^{- 6}} = 50$

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A transistor is operated in common-emitter configuration at VC=2V such that a change in the base current from 100μA to 200μA produces a change in the collector current from 5 mA to 10 mA. The current gain is :

The correct option is A 50ΔIB=100μAΔIC=5mAβ=ΔICΔIB=5×10−3100×10−6=50

A transistor is operated in common-emitter configuration at $V_{C} = 2 V$ such that a change in the base current from $100 μ A$ to $200 μ A$ produces a change in the collector current from 5 mA to 10 mA. The current gain is :

The correct option is A 50
$Δ I_{B} = 100 μ A$
$Δ I_{C} = 5 m A$
$β = \frac{Δ I_{C}}{Δ I_{B}} = \frac{5 \times 10^{- 3}}{100 \times 10^{- 6}} = 50$