A transistor is used in common-emitter configuration- Given its - - 0-9- calculate the change in collector current when the base current changes by 2 - A-

The correct option is C 18 μ A β = α1 α #160; #160; = 0.91 0.9 = 9 β = Δ I_cΔ I_b Δ I_c = 9 × 2 = 18 μ A ...

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Standard XII

Physics

Power in an AC Circuit

A transistor ...

Question

A transistor is used in common-emitter configuration. Given its $α = 0.9$ , calculate the change in collector current when the base current changes by $2 μ A$ .

1 μ A

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0.9 μ A

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30 μ A

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18 μ A

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Solution

The correct option is C $18 μ A$
$β = \frac{α}{1 - α}$
$= \frac{0.9}{1 - 0.9} = 9$

$β = \frac{Δ I_{c}}{Δ I_{b}}$
$Δ I_{c} = 9 \times 2 = 18 μ A$

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A transistor is used in common-emitter configuration. Given its α=0.9, calculate the change in collector current when the base current changes by 2μA.

The correct option is C 18μAβ=α1−α =0.91−0.9=9β=ΔIcΔIbΔIc=9×2=18 μA

A transistor is used in common-emitter configuration. Given its $α = 0.9$ , calculate the change in collector current when the base current changes by $2 μ A$ .

The correct option is C $18 μ A$
$β = \frac{α}{1 - α}$
$= \frac{0.9}{1 - 0.9} = 9$

$β = \frac{Δ I_{c}}{Δ I_{b}}$
$Δ I_{c} = 9 \times 2 = 18 μ A$