You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electrical Oscillations

A transistor-...

Question

A transistor-oscillator using a resonant circuit with an inductor L (of negligible resistance) and a capacitor C in series produce oscillations of frequency f. If L is doubled and C is changed to 4C, the frequency will be:-

\frac{f}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{f}{2 \sqrt{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{f}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $\frac{f}{2 \sqrt{2}}$
f = $\frac{1}{2 π \sqrt{L C}}$ & f $^{^{'}}$ = $\frac{1}{2 π \sqrt{2 L (4 C)}}$
Therefore f $^{^{'}}$ = $(\frac{1}{2 \sqrt{2}}) \frac{1}{2 π \sqrt{L C}}$ = $\frac{f}{2 \sqrt{2}}$

Suggest Corrections

Similar questions

A transistor-oscillator using a resonant circuit with an inductor L (of negligible resistance) and a capacitor C in series produce oscillations of frequency f . If L is doubled and C is changed to 4C, the frequency will be:

Q. A transistor-oscillator using a resonant circuit with an inductor

L

(of negligible resistance) and a capacitor

C

in series produces oscillations of frequency

f

. If

L

is doubled and

C

is changed to

4 C

, the frequency will be

Q. A transistor-oscillator using a resonant circuit with an inductor

L

(of negligible resistance) and a capacitor

C

in series produces oscillations of frequency

f

. If

L

is doubled and

C

is changed to

4 C

, the frequency will be

Q. A resonant A.C. circuit contains a capacitor of capacitance

10^{- 6}

F and an inductor of

10^{- 4}

H. The frequency of oscillations will be :

Q. A resonant ac circuit contains a capacitor of capacitance

10^{- 6} F

and an inductor of

10^{- 4} H

. The frequency of electrical oscillations will be

Join BYJU'S Learning Program

A transistor-oscillator using a resonant circuit with an inductor L (of negligible resistance) and a capacitor C in series produce oscillations of frequency f. If L is doubled and C is changed to 4C, the frequency will be:-

The correct option is D f2√2f = 12π√LC & f′ = 12π√2L(4C)Therefore f′ = (12√2)12π√LC = f2√2

The correct option is D $\frac{f}{2 \sqrt{2}}$
f = $\frac{1}{2 π \sqrt{L C}}$ & f $^{^{'}}$ = $\frac{1}{2 π \sqrt{2 L (4 C)}}$
Therefore f $^{^{'}}$ = $(\frac{1}{2 \sqrt{2}}) \frac{1}{2 π \sqrt{L C}}$ = $\frac{f}{2 \sqrt{2}}$