A transition metal $M$ forms a volatile chloride which has a vapour density of $94.8$ . If it contains $74.75$ % of chlorine the formula of the metal chloride will be:

M {C l}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M {C l}_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M {C l}_{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M {C l}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $M {C l}_{4}$
The correct option is B
Solution:
$74.75$ of chlorine mean 74.75g chlorine present in 100g of metal chloride.
Weight of metal=100g-74.75g=25.25g
Equivaent weight= $\frac{weight of metal}{weight of chlorine} \times 35.5 g$
$\frac{25.25}{74.75} \times 35.5$ =12
valency of metal= $\frac{2 \times V . D}{e q u i v a l e n t w e i g h t o f m e t a l + 35.5} \times 35.5 = 4$
therefore formula of compound = ${M C l}_{4}$

Suggest Corrections

Similar questions

A metal M, forms a volatile chloride containing 65.5% chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula of the chloride. [M = 56, Cl = 35.5]

Q. A metal M forms a volatile chloride containing 65.5% chlorine. If the density of the chloride relative to hydrogen (i.e., V.D.) is 162.5, the molecular formula of the chloride is:

[M = 56; C l = 35.5]

A metal M forms a volatile chloride contaning 65.5 % chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula fo the chloride (M- 56).

A metal M forms a volatile chloride containing 65.5% chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula of the chloride.

[M = 56, Cl = 35.5]

Given: Cl = 65.5%

M = (100-65.5)% = 34.5 %

Q. The chloride of a metal has the formula

M C l_{3}

. The formula of its phosphate will be:

Join BYJU'S Learning Program

A transition metal M forms a volatile chloride which has a vapour density of 94.8. If it contains 74.75% of chlorine the formula of the metal chloride will be:

A transition metal $M$ forms a volatile chloride which has a vapour density of $94.8$ . If it contains $74.75$ % of chlorine the formula of the metal chloride will be: