A transmitting antenna is at a height of $20 m$ and receiving antenna is at a height of $80 m$ . The maximum distance between them for satisfactory communication is

16 k m

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32 k m

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48 k m

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96 k m

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Solution

The correct option is D $48 k m$
$d_{m a x} = \sqrt{2 R H_{T}} + \sqrt{2 R H_{R}} H_{T} = 20 m H_{R} = 80 m \Rightarrow d_{m a x} = \sqrt{\frac{2 \times 6400 \times 20}{1000}} + \sqrt{\frac{2 \times 6400 \times 80}{1000}} \approx 48 k m$

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A transmitting antenna is at a height of 20 m and receiving antenna is at a height of 80 m. The maximum distance between them for satisfactory communication is

The correct option is D 48 kmdmax=√2RHT+√2RHRHT=20mHR=80m⇒dmax=√2×6400×201000+√2×6400×801000≈48km

A transmitting antenna is at a height of $20 m$ and receiving antenna is at a height of $80 m$ . The maximum distance between them for satisfactory communication is

The correct option is D $48 k m$
$d_{m a x} = \sqrt{2 R H_{T}} + \sqrt{2 R H_{R}} H_{T} = 20 m H_{R} = 80 m \Rightarrow d_{m a x} = \sqrt{\frac{2 \times 6400 \times 20}{1000}} + \sqrt{\frac{2 \times 6400 \times 80}{1000}} \approx 48 k m$