A transparent cube of15cm edge contains a small air bubble . Its apparent depth when viewed through one face is 6 cm and when viewed through the opposite face is 4 cm . Then find refractive index of the material

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Solution

Real depth / apparent depth = refractive index

h1 / 6 cm = μ => h1 = 6 μ cm

h2 / 4cm = μ => h2 = 4 μ cm

h1 + h2 = 15 cm = 10 μ => μ = 1.5 cm

The bubble is in the middle of the width of the cube. So real depth from h1 one side face is equal to (15-h1) of the real depth from the opposite face

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A transparent cube of15cm edge contains a small air bubble . Its apparent depth when viewed through one face is 6 cm and when viewed through the opposite face is 4 cm . Then find refractive index of the material

Real depth / apparent depth = refractive index h1 / 6 cm = μ => h1 = 6 μ cm h2 / 4cm = μ => h2 = 4 μ cm h1 + h2 = 15 cm = 10 μ => μ = 1.5 cm The bubble is in the middle of the width of the cube. So real depth from h1 one side face is equal to (15-h1) of the real depth from the opposite face