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Question

A transparent paper (refractive index =1.45) of thickness 0.02 mm is pasted on one of the slits of Young's double slit experiment which uses monochromatic light of wavelength 620 nm. How many fringes will cross through the centre if the paper is removed?

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Solution

Given
The refractive index of the paper is μ=1.45
Thickness of the paper is t=0.02 mm=0.02×103 m
and the wavelength of the light used is λ=620 nm=620×109 m

We know, when the transparent paper is pasted in one of the slits, the optical path changes by (μ1)t.

Again, for a shift of one fringe, the optical path should be changed by λ.

So, no. of fringes crossing through the centre is given by,
n=(μ1)tλ

=0.45×0.02×103620×109=14.5

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