To prove: EP||FQ
Proof:
Given, AB || CD.
⇒ ∠APG=∠CQP [corresponding angles]
⇒ 12 ∠APG=12∠CQP [dividing both sides by 2]
⇒ ∠EPG=∠FQP
[∵ EP and FQ are the bisectors of ∠APG and ∠CQP respectively]
These are the corresponding angles on the transversal line t.
∴ EP || F Q
Hence, proved.