A transverse periodic wave on a string with a linear mass density of 0.200 kg/m is described by the following equation where x and y are in metres and t is in seconds.

$32 N$

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$42 N$

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$66 N$

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$80 N$

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Solution

The correct option is D
$80 N$

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Similar questions

Q. A transverse periodic wave on a string with a mass density of

0.200 k g / m

is described by the following equation

y = 0.05 sin (420 t - 21.0 x)

,
where x and y are in meters and t is in seconds.
The tension in the string is equal to:

A transverse periodic wave on a string with a linear mass density of $0.200$ kg/m is described by the following equation $y = 0.05 sin (420 t - 21.0 x)$ where $x$ and $y$ are in metres and $t$ is in seconds.

The linear density of a vibrating string is $10^{- 4} k g / m$ . A transverse wave is propagating on the string, which is described by the equation y = 0.02 sin (x + 30 t), where x and y are in meters and time t in seconds. Then tension in the string is

Q. A transverse wave propagating on the string can be described by the equation

y = 2 sin (10 x + 300 t) .

where

x

and

y

are in metres and

t

in second. If the vibrating string has linear density of

0.6 \times 10^{- 3} g / c m

then the tension in the string is

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A transverse periodic wave on a string with a linear mass density of 0.200 kg/m is described by the following equation where x and y are in metres and t is in seconds.

The correct option is D 80N

The correct option is D
$80 N$