A transverse wave described by
y=(0.02 m)sin[(1.0 m−1)x+(30 s−1)t]
propagates on a stretched string having a linear mass density of 1.2×10−4kg m−1. Find the tension in the string.
m = mass per unit length
=1.2×10−4kg/m
Y = (0.02 m) sin
[1.0 m−1x+(30 s−1)t]
Here, k=1 m−1=2πλ
w=30s−1=2πf
∴ Velocity of the wave in the stretched string
v=λf=ωk=30I
=30 m/s
⇒v=(Tm)
⇒30=√(T1.2×10−4N)
⇒t=10.8×10−2N
⇒T=0.08 Newton