Question

A transverse wave is represented by:

$y=\frac{10}{\pi }\sin (\frac{2\pi }{T}+\frac{2\pi }{\lambda }X)$For what value of the wavelength the wave velocity is twice the maximum particle velocity?

• A. 40 cm
• B. 20 cm
• C. 10 cm
• D. 60 cm

Answer 1

The correct option is A 40 cm

Wave velocity $\frac{\omega }{K}=\frac{2\pi /T}{2\pi /\lambda }=\frac{\lambda }{T}$

Maximum particle velocity=$\frac{10}{\pi }.\frac{2\pi }{T}=\frac{20}{T}$

$\because \frac{\lambda }{T}=2\left(\frac{20}{T}\right)$

$\Rightarrow \lambda =40cm$