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Question

A transverse wave of amplitude 0.5 m and wavelength 1 m and frequency 2 Hz is propagating in a string in the negative x direction. The expression for this wave is?

A
y=0.5sin(πx2πt)
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B
y=0.5sin(2πx4πt)
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C
y=0.5sin(2πx+4πt)
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D
y=0.5sin(2πx+2πt)
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Solution

The correct option is D y=0.5sin(2πx+4πt)
Equation of a transverse wave propagating in the negative x direction can be written as y=A sin(kx+wt)
Now, amplitude A=0.5 m
Given : λ=1 m ν=2 Hz
So, w=2πν=2π×2=4π
Also, k=2πλ=2π1=2π
So, y=0.5 sin(2πx+4πt)
Option C is correct.

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