A trapezoidal channel is 10.0 m wide at the base and has a side slope of 4 horizontal to 3 vertical. The bed slope is 0.002. The channel is lined with smooth concrete (Manning's n = 0.012). The hydraulic radius (in m) for depth of flow of 3.0 m is
A
3.0
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B
3.5
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C
20.0
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D
2.1
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Solution
The correct option is D 2.1 ∵A=(B+ny)y=(10+43×3)×3 =(10+4)3=42m2 P=B+2y√n2+1 =10+6√(4/3)2+1 =10+6×53=20m ∴R=AP=4220=2.1