A trapezoidal window has its bases as 35 cm and 28 cm respectively. The length of its opposite sides are x and 1.5x.
Find the value of x if the perimeter of the window is 111 cm.

21 cm

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20 cm

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28 cm

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20 cm

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Solution

The correct option is D 20 cm
Lets draw a trapezoid of the given dimensions:
Given,
Perimeter of window = 111 cm

As we know,
Perimeter of trapezoid = sum of all sides
111 = 35 + 1.4 x + 28 + x
111 = 63 + 2.4 x
2.4 x = 48
x $= \frac{48}{2.4} = 20 c m$
Option (d) is correct.

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A trapezoidal window has its bases as 35 cm and 28 cm respectively. The length of its opposite sides are x and 1.5x. Find the value of x if the perimeter of the window is 111 cm.

The correct option is D 20 cmLets draw a trapezoid of the given dimensions: Given, Perimeter of window = 111 cm As we know, Perimeter of trapezoid = sum of all sides 111 = 35 + 1.4 x + 28 + x 111 = 63 + 2.4 x 2.4 x = 48 x =482.4=20 cm Option (d) is correct.

A trapezoidal window has its bases as 35 cm and 28 cm respectively. The length of its opposite sides are x and 1.5x.
Find the value of x if the perimeter of the window is 111 cm.

The correct option is D 20 cm
Lets draw a trapezoid of the given dimensions:
Given,
Perimeter of window = 111 cm

As we know,
Perimeter of trapezoid = sum of all sides
111 = 35 + 1.4 x + 28 + x
111 = 63 + 2.4 x
2.4 x = 48
x $= \frac{48}{2.4} = 20 c m$
Option (d) is correct.