A travelling microscope has $20$ divisions per $c m$ on the main scale while its bernier scale has total $50$ divisions and $25$ vernier scale divisions are equal to $24$ main scale divisions, what is the least count of the travelling microscope?

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Solution

Least count $= 1 MSD - 1 VSD$

$25 VSD = 24 MSD$

$1 VSD = \frac{24}{25} MSD$

$LC = (1 - \frac{24}{25}) MSD = 0.002 cm$

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A microscope has its main scale with 20 divisions in 1 cm and vernier scale with 25 divisions, the length of which is equal to the length of 24 divisions of main scale. The least count of microscope is :

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A travelling microscope has 20 divisions per cm on the main scale while its bernier scale has total 50 divisions and 25 vernier scale divisions are equal to 24 main scale divisions, what is the least count of the travelling microscope?

Least count =1 MSD−1 VSD 25 VSD=24 MSD 1 VSD=2425 MSD LC=(1−2425) MSD=0.002 cm

A travelling microscope has $20$ divisions per $c m$ on the main scale while its bernier scale has total $50$ divisions and $25$ vernier scale divisions are equal to $24$ main scale divisions, what is the least count of the travelling microscope?

Least count $= 1 MSD - 1 VSD$

$25 VSD = 24 MSD$

$1 VSD = \frac{24}{25} MSD$

$LC = (1 - \frac{24}{25}) MSD = 0.002 cm$