A travelling wave has an equation of the form $A (x, t) = f (x + v t)$ . The relation connecting positional derivative with time derivative of the function is:

\frac{d A}{d t} = \pm v^{2} \frac{d A}{d x}

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\frac{d A}{d t} = \pm v \frac{d A}{d x}

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\frac{d A}{d t} = \pm \sqrt{(} v) \frac{d A}{d x}

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\frac{d A}{d t} = (2 π v / λ) \frac{d A}{d x}

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Solution

The correct option is B $\frac{d A}{d t} = \pm v \frac{d A}{d x}$
Positional derivative and time derivative of a function f is $\frac{d A}{d t} = \pm v \frac{d A}{d x}$
The correct option is (b)

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A travelling wave has an equation of the form A(x,t)=f(x+vt). The relation connecting positional derivative with time derivative of the function is:

The correct option is B dAdt=±vdAdxPositional derivative and time derivative of a function f is dAdt=±vdAdxThe correct option is (b)

A travelling wave has an equation of the form $A (x, t) = f (x + v t)$ . The relation connecting positional derivative with time derivative of the function is:

The correct option is B $\frac{d A}{d t} = \pm v \frac{d A}{d x}$
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The correct option is (b)