A travelling wave is having wavelength of $3 cm$ . At any instant, the two particles at a distance of $16.5 cm$ apart, will have a phase difference of,

12 π

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11 π

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10 π

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13 π

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Solution

The correct option is B $11 π$
Given:
$λ = 3 cm$
$Δ x = 16.5 cm$

Phase difference is given by,
$Δ ϕ = k Δ x = \frac{2 π}{λ} \times Δ x$
$∴ Δ ϕ = \frac{2 π}{3} \times 16.5 = 11 π$

So, the phase difference between the given points is $11 π$ .

Hence, $(B)$ is the correct answer.

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A travelling wave is having wavelength of 3 cm. At any instant, the two particles at a distance of 16.5 cm apart, will have a phase difference of,

The correct option is B 11πGiven: λ=3 cm Δx=16.5 cm Phase difference is given by, Δϕ=k Δx=2πλ×Δx ∴Δϕ=2π3×16.5=11π So, the phase difference between the given points is 11π. Hence, (B) is the correct answer.

A travelling wave is having wavelength of $3 cm$ . At any instant, the two particles at a distance of $16.5 cm$ apart, will have a phase difference of,

The correct option is B $11 π$
Given:
$λ = 3 cm$
$Δ x = 16.5 cm$

Phase difference is given by,
$Δ ϕ = k Δ x = \frac{2 π}{λ} \times Δ x$
$∴ Δ ϕ = \frac{2 π}{3} \times 16.5 = 11 π$

So, the phase difference between the given points is $11 π$ .

Hence, $(B)$ is the correct answer.