A travelling wave pulse is given by equation, y=43x2+48t2+24xt+2, where x and y are in metre and t is in second. The wave velocity is
A
4m/s
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B
3m/s
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C
2m/s
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D
1m/s
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Solution
The correct option is A4m/s The given wave equation will represent a travelling wave, if y=f(kx±ωt)
Given:
Wave equation, y=43x2+48t2+24xt+2 ⇒y=43(x2+16t2+8xt)+2 ⇒y=43(x+4t)2+2
On comparing with form, y=f(kx±ωt), we get, k=1 and ω=4
So, wave velocity v=ωk=41=4m/s
Why this question?
It tends to test the understanding of the fundamental format of a travelling wave.