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Question

A travelling wave pulse is given by equation,
y=43x2+48t2+24xt+2, where x and y are in metre and t is in second. The wave velocity is

A
4 m/s
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B
3 m/s
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C
2 m/s
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D
1 m/s
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Solution

The correct option is A 4 m/s
The given wave equation will represent a travelling wave, if y=f(kx±ωt)
Given:
Wave equation,
y=43x2+48t2+24xt+2
y=43(x2+16t2+8xt)+2
y=43(x+4t)2+2
On comparing with form, y=f(kx±ωt), we get,
k=1 and ω=4
So, wave velocity
v=ωk=41=4 m/s
Why this question?
It tends to test the understanding of the fundamental format of a travelling wave.

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