A travelling wave tube is given by y - 0-83x2 - 12 xt - 12t2 - 4- where x and y are in m and t is in s - The velocity of the wave

The correct option is C 2 m/s [ y= 0.8 3 x^ 2 +12xt+12 t^ 2 +4 #160;; = 0.8 3( x^ 2 +4x+4 t^ 2 ) +4 ...

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Standard XII

Physics

Wave Speed expression

A travelling ...

Question

A travelling wave tube is given by
$y = \frac{0.8}{(3 x^{2} + 12 x t + 12 t^{2} + 4)}$ , where x and y are in m and t is in s . The velocity of the wave

3 m/s

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5 m/s

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2 m/s

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7 m/s

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Solution

The correct option is C 2 m/s
$\begin{matrix} y = \frac{0.8}{3 x^{2} + 12 x t + 12 t^{2} + 4} = \frac{0.8}{3 (x^{2} + 4 x + 4 t^{2}) + 4} = \frac{0.8}{3 {(x + 2 t)}^{2} + 4} = \frac{0.8}{3 \times 4 {(\frac{x}{2} + t)}^{2} + 4} ∴ V e l o c i t y = 2 m / s \end{matrix}$
$∴$ Option $C$ is correct.

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A travelling wave tube is given byy=0.8(3x2+12xt+12t2+4), where x and y are in m and t is in s . The velocity of the wave

The correct option is C 2 m/sy=0.83x2+12xt+12t2+4=0.83(x2+4x+4t2)+4=0.83(x+2t)2+4=0.83×4(x2+t)2+4∴Velocity=2m/s∴ Option C is correct.

A travelling wave tube is given by
$y = \frac{0.8}{(3 x^{2} + 12 x t + 12 t^{2} + 4)}$ , where x and y are in m and t is in s . The velocity of the wave

The correct option is C 2 m/s
$\begin{matrix} y = \frac{0.8}{3 x^{2} + 12 x t + 12 t^{2} + 4} = \frac{0.8}{3 (x^{2} + 4 x + 4 t^{2}) + 4} = \frac{0.8}{3 {(x + 2 t)}^{2} + 4} = \frac{0.8}{3 \times 4 {(\frac{x}{2} + t)}^{2} + 4} ∴ V e l o c i t y = 2 m / s \end{matrix}$
$∴$ Option $C$ is correct.