Question

A tree 12m high, is broken by the wind in such a way that its top touches the ground and makes an angle ${60}^{\circ }$ with the ground, height from the bottom the tree is broken by the wind? ($\sqrt{3}$ = 1.73) is 5.52 m
If true then enter $1$ and if false then enter $0$

Answer 1

Angle made by the unbroken tree with ground = ${60}^{\circ }$
Let the height of unbroken part = $h$
Then height of broken part = $12-h$
The broken part, unbroken part and the ground make a right angled triangle.
hence, $\sin 60=\frac{h}{12-h}$
$12\sqrt{3}-h\sqrt{3}=2h$
$h=\frac{12\sqrt{3}}{2+\sqrt{3}}$
$h=5.56$ m