A tree grows annually by one-eighth of its height. By how much will it grow after 2 years, if it stands today 64 cm high?

72 cm

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74 cm

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75 cm

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81 cm

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Solution

The correct option is D 81 cm
Present height of tree=64cm
It grow annually by one-eighth of its height
Then it grow in first year= $\frac{1}{8} \times 64 = 8 c m$
Then total height= $64 + 8 = 72$
In second year it grow = $\frac{1}{8} \times 72 = 9 c m$
then total height after 2 year= $72 + 9 = 81 c m$

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A tree grows annually by one-eighth of its height. By how much will it grow after 2 years, if it stands today 64 cm high?

The correct option is D 81 cmPresent height of tree=64cmIt grow annually by one-eighth of its heightThen it grow in first year=18×64=8cmThen total height=64+8=72In second year it grow =18×72=9cmthen total height after 2 year=72+9=81cm