A tree is broken at certain height and its upper part 9√2 m long not completely separated meet the ground at an angle of 45∘. Find the height of the tree before it was broken and also find the distance from the root of the tree to the point where the top of the tree meets the ground.
The given situation can be represented by the figure below
cos(∠CAB)=ABAC⇒AB=ACAcos(∠CAB)=9√2×cos45∘=9m∴distance of the point from root is 9mAlsosin(∠CAB)=BCAC⇒BC=sin(∠CAB)×AC=sin45∘×9√2=9m∴total height before breaking=9+9√2=9(1+√2)m