A tree planted by Karan is $3$ meters high . Every month the height of the tree increased by $0.2$ m. After how many more months will the tree be $4$ m tall?

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Solution

The given situation forms an A.P. whose first term is $3$ and common difference is $0.2$ .

Therefore,

$3 + (n - 1) 0.2 = 4$

$(n - 1) 0.2 = 1$

$n - 1 = 5$

$n = 6$

Therefore, after $6$ months tree will be $4$ $m$ tall.

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A tree planted by Karan is 3 meters high . Every month the height of the tree increased by 0.2 m. After how many more months will the tree be 4 m tall?

The given situation forms an A.P. whose first term is 3 and common difference is 0.2.Therefore,3+(n−1)0.2=4(n−1)0.2=1n−1=5n=6Therefore, after 6 months tree will be 4m tall.

A tree planted by Karan is $3$ meters high . Every month the height of the tree increased by $0.2$ m. After how many more months will the tree be $4$ m tall?

The given situation forms an A.P. whose first term is $3$ and common difference is $0.2$ .

Therefore,

$3 + (n - 1) 0.2 = 4$

$(n - 1) 0.2 = 1$

$n - 1 = 5$

$n = 6$

Therefore, after $6$ months tree will be $4$ $m$ tall.