A trian of length $200 m$ , travelling at $30 m s^{- 1}$ overtakes another train of length $300 m$ travelling at $20 m s^{- 1}$ . The time taken by the first train to pass the second train is

30 s e c

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50 s e c

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10 s e c

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40 s e c

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Solution

The correct option is B $50 s e c$
Relative velocity of first train w.r.t second train $= 30 - 20 = 10 m / s$
Distance to covered by first train $= 200 + 300 = 500 m$
Time taken $= \frac{d i s p l a c e m e n t}{v e l o c i t y} = \frac{500}{10} = 50 s$

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