A triangle and a parallelogram have the same base and are situated between the same parallels. The ratio of their areas is $?$

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Solution

As we know the Theorem
The area of a triangle is half the area of a parallelogram if they are standing on the same base and between the same parallels.
$A r e a o f T r i a n g l e A B D = \frac{1}{2} \times A r e a o f P a r a l l e \log r a m A B C D$
Hence, the ratio of the area of the triangle to that of the parallelogram $= 1 : 2 .$

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