Question

A triangle ABC in which DE||BC, and intersects AB in D and AC in E
Hence,
$\frac{AB}{DB}=\frac{AC}{EC}$

• A. True
• B. False

Answer 1

The correct option is A True

$\angle ABC=\angle ACB$
$\frac{1}{2}\angle ABC=\frac{1}{2}\angle ACB$
$\angle ABO=\angle ACO$ (I)
In $△ABO$ and $△ACO$,
$\angle ABO=\angle ACO$ (From I)
$AO=AO$ (Common side)
$AB=AC$ (Given)
Thus, $△ABO\cong △ACO$ (SAS rule)
hence, $\angle OAB=\angle OAC$ (By cpct)
Thus, OA bisects $\angle A$