Question

A triangle ABC is constructed with AB = 5 cm, BC = 9 cm and $\angle A={90}^{\circ }$. Then, the length of third side is _______ cm.

• A. 7.48

Answer 1

The correct option is A 7.48

Step 1:
Draw the line segment AB of the length 5 cm.

Step 2:
Measure the angle A with your protractor. Make a mark at 90 degrees and draw a line from A passing through the mark.

Step 3:
Cut an arc of radius 9 cm on the line passing through the point A from point B. The point where this arc cuts the line is the point C.

Step 4:
Draw a line from C to point B to get the required triangle ABC, as shown below.


From the above construction, we see that the measure of side AC is 7.48 cm.